(3x+7)(3-2x)=-6x^2+21-5x

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Solution for (3x+7)(3-2x)=-6x^2+21-5x equation: 



(3x+7)(3-2x)=-6x^2+21-5x

We move all terms to the left:

(3x+7)(3-2x)-(-6x^2+21-5x)=0

We add all the numbers together, and all the variables

-(-6x^2+21-5x)+(3x+7)(-2x+3)=0

We get rid of parentheses

6x^2+5x+(3x+7)(-2x+3)-21=0

We multiply parentheses ..

6x^2+(-6x^2+9x-14x+21)+5x-21=0

We get rid of parentheses

6x^2-6x^2+9x-14x+5x+21-21=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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